What happens to a bullet fired on the moon?
In reference to "Can I fire a gun on the moon?"-- what then happens to the bullet?
First, we know that the bullet has the same initial velocity on the moon as it does on the Earth--that is, it exits the gun at the same speed. But as soon as it leaves the gun, it's a different story. First, the moon bullet doesn't have to contend with air resistance--with so little friction, it can maintain its speed longer than the Earth bullet can (it's analogous to shooting a hockey puck across ice, which has very little friction, and shooting across sand, which has a lot of friction. The puck will travel a lot farther on the ice!)
Now, there is the issue of gravity. Assuming your bullet doesn't hit anything (a pretty safe bet on the moon, but don't try this on Earth!) and forgetting about air restistance, the time it takes for the bullet to fall to the ground depends on its initial velocity, the angle at which you shoot it, and the force of gravity.
You can use some basic physics to figure out how far the bullet will fly horizontally and vertically. Say you fire it at some angle "a" (a=0 degrees would correspond to shooting it straight in front of you; 90 degrees corresponds to shooting it straight up). It turns out that the bullet's horizontal range--the total distance it travels before gravity wrestles it to the ground--is given by the equation:
R = v^2 * sin (2a) / g
g is a measure of the strength of gravity. On Earth, it is 9.8 m/s^2. To find g on the moon, we need another equation:
g = G*M/r^2
Now G called the gravitational contstant, M is the mass of the moon, and r is the radius of the moon. Anyway, on the moon,
g = 1.6 m/s^2
So, neglecting air resistance, the bullet will go about 6 times farther on the moon than on Earth. Once you take air resistance into account, the moon bullet has an even bigger advantage!
You might also ask, if the bullet were fired straight up, could it actually escape the moon's gravitational pull and fly off into space? To answer this, we have to compare the moon's "escape velocity" (the minimum velocity an object needs to esscape the moon's gravity) to the bullet's initial velocity. The moon's escape velocity is about 2.38 km/s, but a bullet typically travels at only 1 km/s. So take cover--even in this case, what goes up must come down!
Get More 'Curious?' with Our New PODCAST:
- Podcast? Subscribe? Tell me about the Ask an Astronomer Podcast
- Subscribe to our Podcast | Listen to our current Episode
- Cool! But I can't now. Send me a quick reminder now for later.
How to ask a question:
If you have a follow-up question concerning the above subject, submit it here. If you have a question about another area of astronomy, find the topic you're interested in from the archive on our site menu, or go here for help.Table 'curious.Referrers' doesn't existTable 'curious.Referrers' doesn't exist
This page has been accessed 49337 times since April 18, 2004.
Last modified: April 18, 2004 12:22:48 PM
Ask an Astronomer is hosted by the Astronomy Department at Cornell University and is produced with PHP and MySQL.
Warning: Your browser is misbehaving! This page might look ugly. (Details)